Calculus with Dr. Bob VI: Sequences and Series
Video Lectures
Displaying all 60 video lectures.
Lecture 1![]() Play Video |
Sequences: Definitions, Squeeze Theorem Calculus: We define sequences, recursive, and the notions of convergence and divergence. Techniques presented are fitting sequences to functions and the Squeeze Theorem. |
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Examples of Sequences Calculus: We define arithmetic and geometric sequences in both their function and recursive forms. |
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Examples of Recursive Sequences Calculus: Further examples of recursive sequences are presented. We also introduce the logistic sequence with various initial conditions. |
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Sequences 1b - Squeeze Theorem/ Monotone Convergence Theorem Calculus: Sequences continue. An example of the Squeeze Theorem is given, we defined monotonic and bounded, and the Monotone Convergence Theorem is stated. |
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Sequences 2 - Examples of Convergent/Monotonic/Bounded Calculus: For the following sequences, we consider (a) convergence/divergence, (b) monotonic increasing/decreasing, and (c) boundedness. (I) a_n = cos(n pi), (II) a_n = cos(n pi)/n^2, (III) a_n = ln(n^{3/2})/n^{3/2}. |
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Sequences 3 - Limit of sqrt(n^2 + n) - n Calculus: We calculate the limit as n goes to infty of sqrt(n^2 + n) - n using two methods. |
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Sequences 4 - Example of Monotone Convergence Theorem Calculus: We apply the Monotone Convergence Theorem to find the limit of the recursive sequence a_0 = 0, a_n = (1+a_{n-1})/(2+a_{n-1}). |
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Infinite Series 1a - Definitions Calculus: Infinite series are defined. The sum is defined as the limit of partial sums of the defining sequence on a_n. Examples given are sum (1/2)^n and sum 2^n. |
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Infinite Series 1b - Geometric Series/ Limit Test for Divergence Calculus: We continue the introduction to infinite series. A formula for the sum of a convergent geometric series is given, and the Limit Test for Divergence is presented. |
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Infinite Series 1c - Telescoping Series Calculus: We consider telescoping series and their construction. Examples are (a) sum 1/(n^2 + n), (b) sum (2n+1)/(n^4+2n^3+n^2), and (c) sum (1/2)^{n+1}. |
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Infinite Series 2 - Example of Convergence/Divergence Calculus: Determine whether the following series converge or diverge: (a) sum (-3)^n, (b) sum (2^n + 3^n)/5^n, (c) sum n/(n+1), (d) sum n^2/ln(n), and (e) sum e^{-n}. |
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Infinite Series 3 - Decimal Expansion of Fractions Calculus: We show how to convert repeating decimals into fractional form. Examples are .(123) and 5.23(12). |
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Fractals Calculus: We introduce elementary fractals as an application of geometric series. Examples are the Cantor set and the Sierpinski triangle. |
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The Integral Test for Series 1a - Definition/ Examples Calculus: The Integral Test for series convergence is stated and explained. Examples are given. (a) sum 1/n, (b) sum e^{-n}. |
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The Integral Test for Series 1b - More Examples/ p-Series Calculus: Further examples of the Integral Test for series convergence are presented. A special case is given as the p-series Test. (a) sum 1/(n ln(n)^2) (b) sum 1/sqrt(n), (b) sum 1/n^2, (c) sum 1/n^4. |
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The Integral Test for Series 2 - More Examples Calculus: We determine convergence or divergence of the following examples using the Integral Test. (a) sum 1/(2n+4), (b) sum (n^2)/(n^3 + 1)^2, (c) sum 2^{-n}. |
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Estimating Sums with the Integral Test Calculus: We show how to use the Integral Test to estimate the error in the partial sums of a convergent series. We find n such that the nth partial sum of sum 1/n^2 is within .1 and .01 of the actual sum pi^2/6. |
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Direct Comparison Test for Series 1 Calculus: The Direct Comparison Test for series convergence is presented and explained. Examples presented are sum 1/(n^2 + n + 1) and 1/(n^{1/3} + 6). We also show how to set up the inequalities needed for the test. |
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Divergence of Series for 1/ln(n) Calculus: The Direct Comparison Test is used to show the divergence of the series sum 1/ln(n). |
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Limit Comparison Test for Series 1 Calculus: We present and explain the Limit Comparison Test for series convergence. The examples sum 1/(n^2 + n + 1) and sum 1/(n^{1/3} + 6) are reworked with the new test. |
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Limit Comparison Test for Series 2 Calculus: We apply the Limit Comparison Test for series convergence to (a) sum 1/(2^n + 6) and (b) sum 1/(2^n + 3n). |
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Rational Function Test for Series Calculus: Let a_n = P(n)/Q(n), where P and Q are nonzero polynomials. We state a test for the convergence or divergence of the series for a_n. Examples are (a) sum (n^2 + 1)/n, (b) sum n/(n^2 + 1), and (c) sum (n^2 + 1)/(n^4 - 6). |
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Alternating Series 1a - Alternating Series Test Calculus: We define alternating series and give a test for convergence. We explain the test through a series of pictures. The example of sum (-1)^{n+1} 1/n is given. |
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Alternating Series 1b - Estimating the Remainder Calculus: We show how to estimate the sum of a convergent alternating series within a given bound using partial sums. We apply our method to the alternating series sum (-1)^{n+1} 1/n. |
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Alternating Series 1c - More Remainder Estimates Calculus: We consider two examples. The geometric series sum (-1/2)^{n+1} can also be represented as an alternating series. We apply the Alternating Series Test, and find the partial sum S_n that is within .01 of the actual sum. In the second example, we apply the AST to sum (-1)^{n+1} ln(n)/n. |
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Absolute Convergence Test Calculus: We show the Absolute Convergence Test for series, and define the notions of absolute and conditional convergence. We also give an example of a conditionally convergent series whose sum changes when the terms are rearranged. |
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The Ratio Test for Series Calculus: The Ratio Test captures convergence of a series by taking the limit of ratios of consecutive terms. A proof is given, and we consider several examples. (a) sum n/2^n, (b) sum (-1)^n 1/n!, (c) general geometric series, (d) general p-series. |
Lecture 28![]() Play Video |
Series Convergence for n!/n^n Calculus: We verify the convergence of the series for n!/n^n by using the Ratio Test and the Direct Comparison Test. For the Ratio Test, we use the limit of (1+1/n)^n equals e. For the Direct Comparison Test, we compare with the p-series 2/n^2. |
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The Root Test for Series Calculus: The Root Test for convergence of series checks the limit of the nth roots of the nth term of the sequence. This series test works best when the general term has exponent n. We test the examples (a) sum 2^n/n^n, (b) sum [n/ln(n)]^n, and (c) the general geometric series. |
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Root Test for Series Sum (1-1/n^2)^{n^3} Calculus: Determine whether the series sum (1-1/n^2)^{n^3} converges or diverges. We show convergence using the root test and an application of L'Hopital's Rule. In addition, we show two instances of substitution to evaluate limits. |
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Series Test Round-Up 1 Part 1: Determine if the following series converge or diverge: (1) sum 2^n(n+1)^2/n! , (2) sum 1/(sqrt(n) (1+sqrt(n))^2), (3) sum (1/2)^n - (1/2)^{n+1}, and (4) sum 1+(-1)^n. |
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Series Test Round-Up 2 Part 2: Determine whether the following series converge or diverge: (5) sum 1/(ln(n)^2), (6) 1 - 1/4 - 1/9 + 1/16 - 1/25 - 1/36 ..., (7) sum (n^5 + 7n + 2)/(n^3 + 3n + 4), (8) sum 3(e-2)^n. |
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Series Test Round-Up 3 Part 3: Determine the convergence or divergence of the series: (9) sum (-1)^n/(n+ln(n)), (10) sum 1/(n+ln(n)), (11) sum cos(n)/n^3, and (12) sum ln(n^n)/(n^{3/2} ln(n)). |
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Motivating Taylor Polynomials 1 We motivate the Taylor coefficient formula by showing how to recover a polynomial from its derivatives at a point. |
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Motivating Taylor Polynomials 2 Calculus: Continuing with Taylor polynomials, we consider a method for improving the degree of accuracy for tangent line approximations by considering higher derivatives. This leads to the definition of Taylor coefficients. we consider the examples of f(x) = x^3+1 at x=1.1 and f(x) = sin(x) at x = 3. |
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Application of Taylor Series: Re-centering Polynomials We rewrite the polynomial P(x) = 2x^3 + 2x^2 + 2x + 3 as a polynomial with center at x=1. The coefficients are calculated using the Taylor coefficient formula. |
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Approximating with Maclaurin Polynomials We calculate the 3rd Maclaurin polynomial for f(x) = ln(1-x) and use it to approximate ln(1.1). The key step is the Taylor polynomial formula. |
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Approximating with Taylor Polynomials We calculate the 3rd Taylor polynomial for f(x) = 1/(x+1) centered at x=1, and use it to approximate 1/(2.1). |
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Fast Maclaurin Polynomial for Rational Function Calculus: Let f(x) = (-x^2+13)/(x+2)(x-1)^2. Find the partial fraction expansion for f(x) and use it to find the second Maclaurin polynomial of f(x). We show two methods for finding the polynomial. |
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Taylor's Theorem for Remainders Calculus: Given a Taylor polynomial for a function f(x) with n+1 derivatives, Taylor's Theorem gives us a method for estimating the error from the actual value. The example of f(x) = x^5 + 1 is given. |
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Taylor's Theorem : Remainder for 1/(1-x) Calculus: We apply Taylor's Theorem to the remainder of f(x) = 1/(1-x) with Maclaurin polynomial P_n(x) = 1 + x + x^2 + ... + x^n. We find the explicit point for equality when x = 1/2 and n = 4. |
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Power Series 1a - Interval and Radius of Convergence We define power series functions and define the interval and radius of convergence. The example of f(x) = sum x^n/n^2 is used as a concrete example for evaluating points. |
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Power Series 1b - Interval of Convergence Using Ratio Test For a given power series function, we show how to find the interval of convergence using the ratio test. Particular care must be applied to the endpoints. Examples used are (a) sum n! x^n, (b) sum (x-1)^n/n!, and (c) sum (x+2)^n/n. |
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Example of Interval of Convergence Using Ratio Test Calculus: Find the interval and radius of convergence of the power series f(x) = sum (2x+1)^n/(n+1)^{1/3}. We use the ratio test to find the open interval and then check the endpoints. The radius is half the length of the interval. |
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Power Series 1c - Interval of Convergence Using Root Test We find the interval and radius of convergence for a power series using the root test. We consider the power series: (a) sum [ln(n)/n]^n x^n (b) sum n^n/e^2n x^n, and (c) sum (n/(n+1))^n x^n. |
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Power Series 1d - Finding the Center We consider power series where the (x-c) terms are not clear. Calculate the interval and radius of convergence of: (a) sum (2x + 4)/n^3, and (b) sum ((1/3) x - 2)/n^3. |
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Power Series with Squares We show how to find the interval of convergence for a power series if an x^2 term results from the ratio test. Examples are (a) sum [(x/4)^n]/n, and (b) 1 - x^2/2! + x^4/4! - ... . |
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Derivative/Antiderivative of a Power Series 1a - Basics We define the derivative and antiderivative of a power series function as a term-by -term process. The interval of convergence remains unchanged, although convergence at the endpoints may change. We revisit the example of sum (x^n)/n^2. |
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Derivative/Antiderivative of a Power Series 1b - Interval of Convergence We show how to calculate the interval of convergence of f'(x) when the IC of f(x) is obtained by the ratio test. A similar method is used for the IC of the antiderivative of f(x). An example using the power series for f(x) = e^{x-1} is given. |
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Derivative/Antiderivative of a Power Series 1c - More Examples We find the derivatives and antiderivatives of the power series functions (a) f(x) = 1 + x + x^2 + x^3 + ..., and (b) f(x) = 1 - x^2/2! + x^4/4! - .... |
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Increasing the Interval of Convergence We consider the function f(x) = 1/(x+1) as represented as a power series function centered at x=0 and x=1. We note that moving the center away from the vertical asymptote allows for a bigger interval of convergence. |
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Constructing Power Series from Functions 1a - Geometric Power Series We use the geometric power series to turn rational functions into power series functions. We represent f(x) = 1/(2x+6) as power series centered at x=0 and x=1. |
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Constructing Power Series from Functions 1b - More Geometric Power Series Continuing with constructions based on the geometric power series, we use partial fractions to find the power series of f(x) = 1/(x^2 + x) centered at x=1. As a second example, we find a series representation for pi based on a power series function for tan^{-1}(x) centered at x=0. |
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Constructing Power Series from Functions 1c - Taylor Coefficients Calculus: We give a method for associating a power series to a function when the geometric power series does not apply. Taylor and Maclaurin series are defined, and we show how to extract coefficients from (1+x)^50 using Taylor coefficients. We also note shortcomings in assigning a series to a function. |
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The Taylor Series for f(x) = ln(x) at x = 1 Calculus: We derive the Taylor series for f(x) = ln(x) at x = 1 and use the 4th Taylor polynomial to estimate ln(.9). We then apply Taylor's Theorem to obtain a bound for the error. |
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The Maclaurin Series for f(x) = 1/(1-x)^2 Calculus: We find the Maclaurin series for f(x) = 1/(1-x)^2 as 1 + 2x + 3x^2 + ... by using three different methods: (a) Derivative of power series, (b) product of power series, and (c) Taylor coefficient formula. |
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The Maclaurin Series for f(x) = e^x Calculus: We derive the Maclaurin series for e^x and estimate e^{-1} by way of the error estimate for alternating series. |
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The Maclaurin Series for sin(x), cos(x), and tan(x) Calculus: We compute the Maclaurin series for f(x) = sin(x) using the Taylor coefficient formula. The series for cos(x) is obtained by differentiation. From these, we show how to divide one series into another to obtain the first few terms for the series of tan(x). |
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The Maclaurin Series of f(x) = (1+x)^{1/2} 1a Calculus: We derive the Maclaurin series of f(x) = sqrt(1+x) and use it to compute the series for 1/sqrt(1+x). With this, we obtain the series for sin^{-1}(x), and, in turn, calculate an estimate of sin{-1}(1/2) = pi/6. |
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The Maclaurin Series for f(x) = (1+x)^{1/2} 1b Calculus: We use the Maclaurin series for (1+x)^{1/2} to obtain an estimate for the definite integral int_0^1 (1+x^4)^{1/2} dx. A bound for the error is given using the rule for alternating series. |